56+(2x+4)+x=1808

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Solution for 56+(2x+4)+x=1808 equation: 



56+(2x+4)+x=1808

We move all terms to the left:

56+(2x+4)+x-(1808)=0

We add all the numbers together, and all the variables

x+(2x+4)-1752=0

We get rid of parentheses

x+2x+4-1752=0

We add all the numbers together, and all the variables

3x-1748=0

We move all terms containing x to the left, all other terms to the right

3x=1748

x=1748/3

x=582+2/3

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