5481=21x(21x+24)

Solution for 5481=21x(21x+24) equation:

5481=21x(21x+24)

We move all terms to the left:

5481-(21x(21x+24))=0


We calculate terms in parentheses: -(21x(21x+24)), so:

21x(21x+24)

We multiply parentheses

441x^2+504x

Back to the equation:

-(441x^2+504x)


We get rid of parentheses

-441x^2-504x+5481=0

a = -441; b = -504; c = +5481;
Δ = b2-4ac
Δ = -5042-4·(-441)·5481
Δ = 9922500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9922500}=3150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-504)-3150}{2*-441}=\frac{-2646}{-882}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-504)+3150}{2*-441}=\frac{3654}{-882}
=-4+1/7
$