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540=x(2-x)
We move all terms to the left:
540-(x(2-x))=0
We add all the numbers together, and all the variables
-(x(-1x+2))+540=0
We calculate terms in parentheses: -(x(-1x+2)), so:We get rid of parentheses
x(-1x+2)
We multiply parentheses
-1x^2+2x
Back to the equation:
-(-1x^2+2x)
1x^2-2x+540=0
We add all the numbers together, and all the variables
x^2-2x+540=0
a = 1; b = -2; c = +540;
Δ = b2-4ac
Δ = -22-4·1·540
Δ = -2156
Delta is less than zero, so there is no solution for the equation
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