540=95+(3x+23)+(9x-6)+90+(7x-4)

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Solution for 540=95+(3x+23)+(9x-6)+90+(7x-4) equation: 



540=95+(3x+23)+(9x-6)+90+(7x-4)

We move all terms to the left:

540-(95+(3x+23)+(9x-6)+90+(7x-4))=0



We calculate terms in parentheses: -(95+(3x+23)+(9x-6)+90+(7x-4)), so:

95+(3x+23)+(9x-6)+90+(7x-4)

determiningTheFunctionDomain
(3x+23)+(9x-6)+(7x-4)+95+90

We add all the numbers together, and all the variables

(3x+23)+(9x-6)+(7x-4)+185

We get rid of parentheses

3x+9x+7x+23-6-4+185

We add all the numbers together, and all the variables

19x+198

Back to the equation:

-(19x+198)



We get rid of parentheses

-19x-198+540=0

We add all the numbers together, and all the variables

-19x+342=0

We move all terms containing x to the left, all other terms to the right

-19x=-342

x=-342/-19

x=+18

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