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540=90+b+3/2b+(b+45)+(2b-90)
We move all terms to the left:
540-(90+b+3/2b+(b+45)+(2b-90))=0
Domain of the equation: 2b+(b+45)+(2b-90))!=0We multiply all the terms by the denominator
b∈R
-(90+b+3+540*2b+(b+45)+(2b-90))=0
We calculate terms in parentheses: -(90+b+3+540*2b+(b+45)+(2b-90)), so:We get rid of parentheses
90+b+3+540*2b+(b+45)+(2b-90)
determiningTheFunctionDomain b+540*2b+(b+45)+(2b-90)+90+3
We add all the numbers together, and all the variables
b+540*2b+(b+45)+(2b-90)+93
Wy multiply elements
b+1080b+(b+45)+(2b-90)+93
We get rid of parentheses
b+1080b+b+2b+45-90+93
We add all the numbers together, and all the variables
1084b+48
Back to the equation:
-(1084b+48)
-1084b-48=0
We move all terms containing b to the left, all other terms to the right
-1084b=48
b=48/-1084
b=-12/271
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