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54/2x=3x
We move all terms to the left:
54/2x-(3x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-3x+54/2x=0
We multiply all the terms by the denominator
-3x*2x+54=0
Wy multiply elements
-6x^2+54=0
a = -6; b = 0; c = +54;
Δ = b2-4ac
Δ = 02-4·(-6)·54
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*-6}=\frac{-36}{-12} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*-6}=\frac{36}{-12} =-3 $
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