53=7/10c+11

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Solution for 53=7/10c+11 equation: 



53=7/10c+11

We move all terms to the left:

53-(7/10c+11)=0



Domain of the equation: 10c+11)!=0

c∈R



We get rid of parentheses

-7/10c-11+53=0

We multiply all the terms by the denominator


-11*10c+53*10c-7=0

Wy multiply elements

-110c+530c-7=0

We add all the numbers together, and all the variables

420c-7=0

We move all terms containing c to the left, all other terms to the right

420c=7

c=7/420

c=1/60

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