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53=1/2(x-35)
We move all terms to the left:
53-(1/2(x-35))=0
Domain of the equation: 2(x-35))!=0We multiply all the terms by the denominator
x∈R
-(1+53*2(x-35))=0
We calculate terms in parentheses: -(1+53*2(x-35)), so:
1+53*2(x-35)
determiningTheFunctionDomain 53*2(x-35)+1
Wy multiply elements
106x(x+1
Back to the equation:
-(106x(x+1)
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| 6)7p=56 | | 9=2(d-4)+1 | | -0.75(b+10)=-1.5 | | 10=2(d−3) | | -2(6x-2)-1=-5x-4 | | 9=3(q−4) | | 14x-29=90 | | 12-14a=-15a+5 | | 40u=5 | | 2)x-6=13 | | 2(j−2)=8 | | 4x/7+5=-4 | | Y=82(1.045)^x | | v=(4/3)(3.14)*2.76^3 | | 12+-14a=-15a+5 | | k/7+63=73 | | 2/3x+9=-13 | | 12-14a=15a+5 | | (4x+11)+(14x+29)=180 | | 14-8=m | | 13=4;n=52 | | 100.00+35.00x=370.00-165.00 | | 15(30x−5)=7−2(3+x)−4x | | -2.4b=14.40 | | x+4=-14-x | | 2x2+15-15=0 | | 7−2x=2x−7 | | 100.00+35.00x= | | 7−2x=2x−77 | | -4/7x=3/10 | | q-80/5=4 | | –4y+17=–19 |