53=(y-2)-2(3y-2)

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Solution for 53=(y-2)-2(3y-2) equation: 



53=(y-2)-2(3y-2)

We move all terms to the left:

53-((y-2)-2(3y-2))=0



We calculate terms in parentheses: -((y-2)-2(3y-2)), so:

(y-2)-2(3y-2)

We multiply parentheses

(y-2)-6y+4

We get rid of parentheses

y-6y-2+4

We add all the numbers together, and all the variables

-5y+2

Back to the equation:

-(-5y+2)



We get rid of parentheses

5y-2+53=0

We add all the numbers together, and all the variables

5y+51=0

We move all terms containing y to the left, all other terms to the right

5y=-51

y=-51/5

y=-10+1/5

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