53=(2y+2)+(3y+1)

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Solution for 53=(2y+2)+(3y+1) equation: 



53=(2y+2)+(3y+1)

We move all terms to the left:

53-((2y+2)+(3y+1))=0



We calculate terms in parentheses: -((2y+2)+(3y+1)), so:

(2y+2)+(3y+1)

We get rid of parentheses

2y+3y+2+1

We add all the numbers together, and all the variables

5y+3

Back to the equation:

-(5y+3)



We get rid of parentheses

-5y-3+53=0

We add all the numbers together, and all the variables

-5y+50=0

We move all terms containing y to the left, all other terms to the right

-5y=-50

y=-50/-5

y=+10

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