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52=32-5(x-1)
We move all terms to the left:
52-(32-5(x-1))=0
We calculate terms in parentheses: -(32-5(x-1)), so:We get rid of parentheses
32-5(x-1)
determiningTheFunctionDomain -5(x-1)+32
We multiply parentheses
-5x+5+32
We add all the numbers together, and all the variables
-5x+37
Back to the equation:
-(-5x+37)
5x-37+52=0
We add all the numbers together, and all the variables
5x+15=0
We move all terms containing x to the left, all other terms to the right
5x=-15
x=-15/5
x=-3
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