52=-8(2+c)-20

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Solution for 52=-8(2+c)-20 equation: 



52=-8(2+c)-20

We move all terms to the left:

52-(-8(2+c)-20)=0

We add all the numbers together, and all the variables

-(-8(c+2)-20)+52=0



We calculate terms in parentheses: -(-8(c+2)-20), so:

-8(c+2)-20

We multiply parentheses

-8c-16-20

We add all the numbers together, and all the variables

-8c-36

Back to the equation:

-(-8c-36)



We get rid of parentheses

8c+36+52=0

We add all the numbers together, and all the variables

8c+88=0

We move all terms containing c to the left, all other terms to the right

8c=-88

c=-88/8

c=-11

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