52-(3c+4)=4(c+4)+c

Solution for 52-(3c+4)=4(c+4)+c equation:

Simplifying
52 + -1(3c + 4) = 4(c + 4) + c

Reorder the terms:
52 + -1(4 + 3c) = 4(c + 4) + c
52 + (4 * -1 + 3c * -1) = 4(c + 4) + c
52 + (-4 + -3c) = 4(c + 4) + c

Combine like terms: 52 + -4 = 48
48 + -3c = 4(c + 4) + c

Reorder the terms:
48 + -3c = 4(4 + c) + c
48 + -3c = (4 * 4 + c * 4) + c
48 + -3c = (16 + 4c) + c

Combine like terms: 4c + c = 5c
48 + -3c = 16 + 5c

Solving
48 + -3c = 16 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
48 + -3c + -5c = 16 + 5c + -5c

Combine like terms: -3c + -5c = -8c
48 + -8c = 16 + 5c + -5c

Combine like terms: 5c + -5c = 0
48 + -8c = 16 + 0
48 + -8c = 16

Add '-48' to each side of the equation.
48 + -48 + -8c = 16 + -48

Combine like terms: 48 + -48 = 0
0 + -8c = 16 + -48
-8c = 16 + -48

Combine like terms: 16 + -48 = -32
-8c = -32

Divide each side by '-8'.
c = 4

Simplifying
c = 4