52-(3c+4)=(c+6)+6

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Solution for 52-(3c+4)=(c+6)+6 equation: 



52-(3c+4)=(c+6)+6

We move all terms to the left:

52-(3c+4)-((c+6)+6)=0

We get rid of parentheses

-3c-((c+6)+6)-4+52=0



We calculate terms in parentheses: -((c+6)+6), so:

(c+6)+6

We get rid of parentheses

c+6+6

We add all the numbers together, and all the variables

c+12

Back to the equation:

-(c+12)



We add all the numbers together, and all the variables

-3c-(c+12)+48=0

We get rid of parentheses

-3c-c-12+48=0

We add all the numbers together, and all the variables

-4c+36=0

We move all terms containing c to the left, all other terms to the right

-4c=-36

c=-36/-4

c=+9

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