52-(2c+4)=(c+5)+5

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Solution for 52-(2c+4)=(c+5)+5 equation: 



52-(2c+4)=(c+5)+5

We move all terms to the left:

52-(2c+4)-((c+5)+5)=0

We get rid of parentheses

-2c-((c+5)+5)-4+52=0



We calculate terms in parentheses: -((c+5)+5), so:

(c+5)+5

We get rid of parentheses

c+5+5

We add all the numbers together, and all the variables

c+10

Back to the equation:

-(c+10)



We add all the numbers together, and all the variables

-2c-(c+10)+48=0

We get rid of parentheses

-2c-c-10+48=0

We add all the numbers together, and all the variables

-3c+38=0

We move all terms containing c to the left, all other terms to the right

-3c=-38

c=-38/-3

c=12+2/3

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