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51/2x+2=4x-2
We move all terms to the left:
51/2x+2-(4x-2)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
51/2x-4x+2+2=0
We multiply all the terms by the denominator
-4x*2x+2*2x+2*2x+51=0
Wy multiply elements
-8x^2+4x+4x+51=0
We add all the numbers together, and all the variables
-8x^2+8x+51=0
a = -8; b = 8; c = +51;
Δ = b2-4ac
Δ = 82-4·(-8)·51
Δ = 1696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1696}=\sqrt{16*106}=\sqrt{16}*\sqrt{106}=4\sqrt{106}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{106}}{2*-8}=\frac{-8-4\sqrt{106}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{106}}{2*-8}=\frac{-8+4\sqrt{106}}{-16} $
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