51-(2c+3)=4C+20+C

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Solution for 51-(2c+3)=4C+20+C equation: 


Simplifying
51 + -1(2c + 3) = 4C + 20 + C

Reorder the terms:
51 + -1(3 + 2c) = 4C + 20 + C
51 + (3 * -1 + 2c * -1) = 4C + 20 + C
51 + (-3 + -2c) = 4C + 20 + C

Combine like terms: 51 + -3 = 48
48 + -2c = 4C + 20 + C

Reorder the terms:
48 + -2c = 20 + 4C + C

Combine like terms: 4C + C = 5C
48 + -2c = 20 + 5C

Solving
48 + -2c = 20 + 5C

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-48' to each side of the equation.
48 + -48 + -2c = 20 + -48 + 5C

Combine like terms: 48 + -48 = 0
0 + -2c = 20 + -48 + 5C
-2c = 20 + -48 + 5C

Combine like terms: 20 + -48 = -28
-2c = -28 + 5C

Divide each side by '-2'.
c = 14 + -2.5C

Simplifying
c = 14 + -2.5C

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