51-(2c+3)=4(c+5)+c

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Solution for 51-(2c+3)=4(c+5)+c equation: 


Simplifying
51 + -1(2c + 3) = 4(c + 5) + c

Reorder the terms:
51 + -1(3 + 2c) = 4(c + 5) + c
51 + (3 * -1 + 2c * -1) = 4(c + 5) + c
51 + (-3 + -2c) = 4(c + 5) + c

Combine like terms: 51 + -3 = 48
48 + -2c = 4(c + 5) + c

Reorder the terms:
48 + -2c = 4(5 + c) + c
48 + -2c = (5 * 4 + c * 4) + c
48 + -2c = (20 + 4c) + c

Combine like terms: 4c + c = 5c
48 + -2c = 20 + 5c

Solving
48 + -2c = 20 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
48 + -2c + -5c = 20 + 5c + -5c

Combine like terms: -2c + -5c = -7c
48 + -7c = 20 + 5c + -5c

Combine like terms: 5c + -5c = 0
48 + -7c = 20 + 0
48 + -7c = 20

Add '-48' to each side of the equation.
48 + -48 + -7c = 20 + -48

Combine like terms: 48 + -48 = 0
0 + -7c = 20 + -48
-7c = 20 + -48

Combine like terms: 20 + -48 = -28
-7c = -28

Divide each side by '-7'.
c = 4

Simplifying
c = 4

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