51(2c+3)=4(c+5)+c

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Solution for 51(2c+3)=4(c+5)+c equation: 


Simplifying
51(2c + 3) = 4(c + 5) + c

Reorder the terms:
51(3 + 2c) = 4(c + 5) + c
(3 * 51 + 2c * 51) = 4(c + 5) + c
(153 + 102c) = 4(c + 5) + c

Reorder the terms:
153 + 102c = 4(5 + c) + c
153 + 102c = (5 * 4 + c * 4) + c
153 + 102c = (20 + 4c) + c

Combine like terms: 4c + c = 5c
153 + 102c = 20 + 5c

Solving
153 + 102c = 20 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
153 + 102c + -5c = 20 + 5c + -5c

Combine like terms: 102c + -5c = 97c
153 + 97c = 20 + 5c + -5c

Combine like terms: 5c + -5c = 0
153 + 97c = 20 + 0
153 + 97c = 20

Add '-153' to each side of the equation.
153 + -153 + 97c = 20 + -153

Combine like terms: 153 + -153 = 0
0 + 97c = 20 + -153
97c = 20 + -153

Combine like terms: 20 + -153 = -133
97c = -133

Divide each side by '97'.
c = -1.371134021

Simplifying
c = -1.371134021

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