50y2+120y+72=0

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Solution for 50y2+120y+72=0 equation:



50y^2+120y+72=0
a = 50; b = 120; c = +72;
Δ = b2-4ac
Δ = 1202-4·50·72
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-120}{100}=-1+1/5$

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