50x2-24x-35=0

Solution for 50x2-24x-35=0 equation:

50x^2-24x-35=0

a = 50; b = -24; c = -35;
Δ = b2-4ac
Δ = -242-4·50·(-35)
Δ = 7576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7576}=\sqrt{4*1894}=\sqrt{4}*\sqrt{1894}=2\sqrt{1894}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{1894}}{2*50}=\frac{24-2\sqrt{1894}}{100}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{1894}}{2*50}=\frac{24+2\sqrt{1894}}{100}
$