50=5/6(-24-12b)

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Solution for 50=5/6(-24-12b) equation: 



50=5/6(-24-12b)

We move all terms to the left:

50-(5/6(-24-12b))=0



Domain of the equation: 6(-24-12b))!=0

b∈R



We add all the numbers together, and all the variables

-(5/6(-12b-24))+50=0

We multiply all the terms by the denominator


-(5+50*6(-12b-24))=0



We calculate terms in parentheses: -(5+50*6(-12b-24)), so:

5+50*6(-12b-24)

determiningTheFunctionDomain
50*6(-12b-24)+5

Wy multiply elements

300b(-+5

We use the square of the difference formula

300b(-5

Back to the equation:

-(300b(-5)





We calculate terms in parentheses: -(300b(-5), so:

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