50=5(s+12)+-4(-s+3)

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Solution for 50=5(s+12)+-4(-s+3) equation: 



50=5(s+12)+-4(-s+3)

We move all terms to the left:

50-(5(s+12)+-4(-s+3))=0

We add all the numbers together, and all the variables

-(5(s+12)+-4(-1s+3))+50=0

We use the square of the difference formula

-(5(s+12)-4(-1s+3))+50=0



We calculate terms in parentheses: -(5(s+12)-4(-1s+3)), so:

5(s+12)-4(-1s+3)

We multiply parentheses

5s+4s+60-12

We add all the numbers together, and all the variables

9s+48

Back to the equation:

-(9s+48)



We get rid of parentheses

-9s-48+50=0

We add all the numbers together, and all the variables

-9s+2=0

We move all terms containing s to the left, all other terms to the right

-9s=-2

s=-2/-9

s=2/9

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