50=(x-3)+(5-6x)

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Solution for 50=(x-3)+(5-6x) equation: 



50=(x-3)+(5-6x)

We move all terms to the left:

50-((x-3)+(5-6x))=0

We add all the numbers together, and all the variables

-((x-3)+(-6x+5))+50=0



We calculate terms in parentheses: -((x-3)+(-6x+5)), so:

(x-3)+(-6x+5)

We get rid of parentheses

x-6x-3+5

We add all the numbers together, and all the variables

-5x+2

Back to the equation:

-(-5x+2)



We get rid of parentheses

5x-2+50=0

We add all the numbers together, and all the variables

5x+48=0

We move all terms containing x to the left, all other terms to the right

5x=-48

x=-48/5

x=-9+3/5

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