50=(x-2)(x+3)

Solution for 50=(x-2)(x+3) equation:

50=(x-2)(x+3)

We move all terms to the left:

50-((x-2)(x+3))=0

We multiply parentheses ..

-((+x^2+3x-2x-6))+50=0


We calculate terms in parentheses: -((+x^2+3x-2x-6)), so:

(+x^2+3x-2x-6)

We get rid of parentheses

x^2+3x-2x-6

We add all the numbers together, and all the variables

x^2+x-6

Back to the equation:

-(x^2+x-6)


We get rid of parentheses

-x^2-x+6+50=0

We add all the numbers together, and all the variables

-1x^2-1x+56=0

a = -1; b = -1; c = +56;
Δ = b2-4ac
Δ = -12-4·(-1)·56
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-15}{2*-1}=\frac{-14}{-2}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+15}{2*-1}=\frac{16}{-2}
=-8
$