50=(x+1)/(2-x)

Solution for 50=(x+1)/(2-x) equation:

50=(x+1)/(2-x)

We move all terms to the left:

50-((x+1)/(2-x))=0


Domain of the equation: (2-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-2

x!=-2/1

x!=-2

x∈R


We add all the numbers together, and all the variables

-((x+1)/(-1x+2))+50=0

We multiply all the terms by the denominator


-((x+1)+50*(-1x+2))=0


We calculate terms in parentheses: -((x+1)+50*(-1x+2)), so:

(x+1)+50*(-1x+2)

We multiply parentheses

(x+1)-50x+100

We get rid of parentheses

x-50x+1+100

We add all the numbers together, and all the variables

-49x+101

Back to the equation:

-(-49x+101)


We get rid of parentheses

49x-101=0

We move all terms containing x to the left, all other terms to the right

49x=101

x=101/49

x=2+3/49