500q+700(1-q)=800q+500(1-q)

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Solution for 500q+700(1-q)=800q+500(1-q) equation: 



500q+700(1-q)=800q+500(1-q)

We move all terms to the left:

500q+700(1-q)-(800q+500(1-q))=0

We add all the numbers together, and all the variables

500q+700(-1q+1)-(800q+500(-1q+1))=0

We multiply parentheses

500q-700q-(800q+500(-1q+1))+700=0



We calculate terms in parentheses: -(800q+500(-1q+1)), so:

800q+500(-1q+1)

We multiply parentheses

800q-500q+500

We add all the numbers together, and all the variables

300q+500

Back to the equation:

-(300q+500)



We add all the numbers together, and all the variables

-200q-(300q+500)+700=0

We get rid of parentheses

-200q-300q-500+700=0

We add all the numbers together, and all the variables

-500q+200=0

We move all terms containing q to the left, all other terms to the right

-500q=-200

q=-200/-500

q=2/5

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