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50/x=10x=
We move all terms to the left:
50/x-(10x)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
-10x+50/x=0
We multiply all the terms by the denominator
-10x*x+50=0
Wy multiply elements
-10x^2+50=0
a = -10; b = 0; c = +50;
Δ = b2-4ac
Δ = 02-4·(-10)·50
Δ = 2000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2000}=\sqrt{400*5}=\sqrt{400}*\sqrt{5}=20\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{5}}{2*-10}=\frac{0-20\sqrt{5}}{-20} =-\frac{20\sqrt{5}}{-20} =-\frac{\sqrt{5}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{5}}{2*-10}=\frac{0+20\sqrt{5}}{-20} =\frac{20\sqrt{5}}{-20} =\frac{\sqrt{5}}{-1} $
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