50/n=n-10

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Solution for 50/n=n-10 equation:


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

50/n = n-10 // - n-10

50/n-n+10 = 0

50*n^-1-1*n^1+10*n^0 = 0

(10*n^1-1*n^2+50*n^0)/(n^1) = 0 // * n^2

n^1*(10*n^1-1*n^2+50*n^0) = 0

n^1

10*n-n^2+50 = 0

10*n-n^2+50 = 0

DELTA = 10^2-(-1*4*50)

DELTA = 300

DELTA > 0

n = (300^(1/2)-10)/(-1*2) or n = (-300^(1/2)-10)/(-1*2)

n = (10*3^(1/2)-10)/(-2) or n = (-10*3^(1/2)-10)/(-2)

n in { (10*3^(1/2)-10)/(-2), (-10*3^(1/2)-10)/(-2)}

n in { (10*3^(1/2)-10)/(-2), (-10*3^(1/2)-10)/(-2) }

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