50/5x+20/2x=7

Solution for 50/5x+20/2x=7 equation:

50/5x+20/2x=7

We move all terms to the left:

50/5x+20/2x-(7)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We calculate fractions


100x/10x^2+100x/10x^2-7=0

We multiply all the terms by the denominator


100x+100x-7*10x^2=0

We add all the numbers together, and all the variables

200x-7*10x^2=0

Wy multiply elements

-70x^2+200x=0

a = -70; b = 200; c = 0;
Δ = b2-4ac
Δ = 2002-4·(-70)·0
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-200}{2*-70}=\frac{-400}{-140}
=2+6/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+200}{2*-70}=\frac{0}{-140}
=0
$