50-80(1-z)=50z

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Solution for 50-80(1-z)=50z equation: 



50-80(1-z)=50z

We move all terms to the left:

50-80(1-z)-(50z)=0

We add all the numbers together, and all the variables

-80(-1z+1)-50z+50=0

We add all the numbers together, and all the variables

-50z-80(-1z+1)+50=0

We multiply parentheses

-50z+80z-80+50=0

We add all the numbers together, and all the variables

30z-30=0

We move all terms containing z to the left, all other terms to the right

30z=30

z=30/30

z=1

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