50+(5c-12)+(4c-11)=180

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Solution for 50+(5c-12)+(4c-11)=180 equation: 



50+(5c-12)+(4c-11)=180

We move all terms to the left:

50+(5c-12)+(4c-11)-(180)=0

We add all the numbers together, and all the variables

(5c-12)+(4c-11)-130=0

We get rid of parentheses

5c+4c-12-11-130=0

We add all the numbers together, and all the variables

9c-153=0

We move all terms containing c to the left, all other terms to the right

9c=153

c=153/9

c=17

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