50(2x)(3x-10)=180

Solution for 50(2x)(3x-10)=180 equation:

50(2x)(3x-10)=180

We move all terms to the left:

50(2x)(3x-10)-(180)=0

We multiply parentheses

1506x^2-5020x-180=0

a = 1506; b = -5020; c = -180;
Δ = b2-4ac
Δ = -50202-4·1506·(-180)
Δ = 26284720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{26284720}=\sqrt{16*1642795}=\sqrt{16}*\sqrt{1642795}=4\sqrt{1642795}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5020)-4\sqrt{1642795}}{2*1506}=\frac{5020-4\sqrt{1642795}}{3012}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5020)+4\sqrt{1642795}}{2*1506}=\frac{5020+4\sqrt{1642795}}{3012}
$