5/z+2=10/2z+4

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Solution for 5/z+2=10/2z+4 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

5/z+2 = (10/2)*z+4 // - (10/2)*z+4

5/z-((10/2)*z)-4+2 = 0

5/z-5*z-4+2 = 0

5*z^-1-5*z^1-2*z^0 = 0

(5*z^0-5*z^2-2*z^1)/(z^1) = 0 // * z^2

z^1*(5*z^0-5*z^2-2*z^1) = 0

z^1

5-5*z^2-2*z = 0

5-5*z^2-2*z = 0

DELTA = (-2)^2-(-5*4*5)

DELTA = 104

DELTA > 0

z = (104^(1/2)+2)/(-5*2) or z = (2-104^(1/2))/(-5*2)

z = (2*26^(1/2)+2)/(-10) or z = (2-2*26^(1/2))/(-10)

z in { (2*26^(1/2)+2)/(-10), (2-2*26^(1/2))/(-10)} 

z in { (2*26^(1/2)+2)/(-10), (2-2*26^(1/2))/(-10) }

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