5/y+1=4/y+2

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Solution for 5/y+1=4/y+2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

5/y+1 = 4/y+2 // - 4/y+2

5/y-(4/y)-2+1 = 0

5/y-4*y^-1-2+1 = 0

1*y^-1 = 1 // : 1

y^-1 = 1

-1 < 0

1/(y^1) = 1 // * y^1

1 = 1*y^1 // : 1

1 = y^1

y = 1

y = 1

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