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5/x=8/2x-6
We move all terms to the left:
5/x-(8/2x-6)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x-6)!=0We get rid of parentheses
x∈R
5/x-8/2x+6=0
We calculate fractions
10x/2x^2+(-8x)/2x^2+6=0
We multiply all the terms by the denominator
10x+(-8x)+6*2x^2=0
Wy multiply elements
12x^2+10x+(-8x)=0
We get rid of parentheses
12x^2+10x-8x=0
We add all the numbers together, and all the variables
12x^2+2x=0
a = 12; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·12·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*12}=\frac{-4}{24} =-1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*12}=\frac{0}{24} =0 $
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