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5/x=10/2x-1
We move all terms to the left:
5/x-(10/2x-1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x-1)!=0We get rid of parentheses
x∈R
5/x-10/2x+1=0
We calculate fractions
10x/2x^2+(-10x)/2x^2+1=0
We multiply all the terms by the denominator
10x+(-10x)+1*2x^2=0
Wy multiply elements
2x^2+10x+(-10x)=0
We get rid of parentheses
2x^2+10x-10x=0
We add all the numbers together, and all the variables
2x^2=0
a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{4}=0$
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