5/x-2-20/(x-2)(x+2)=1

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Solution for 5/x-2-20/(x-2)(x+2)=1 equation: 


D( x )

x-2 = 0

x = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x = 0

x = 0

x in (-oo:0) U (0:2) U (2:+oo)

5/x-((20/(x-2))*(x+2))-2 = 1 // - 1

5/x-((20/(x-2))*(x+2))-2-1 = 0

5/x-20*(x+2)*(x-2)^-1-2-1 = 0

(-20*(x+2))/(x-2)+5/x-2-1 = 0

(-20*x*(x+2))/(x*(x-2))+(5*(x-2))/(x*(x-2))+(-2*x*(x-2))/(x*(x-2))+(-1*x*(x-2))/(x*(x-2)) = 0

5*(x-2)-20*x*(x+2)-2*x*(x-2)-1*x*(x-2) = 0

4*x-20*x^2-2*x^2-x^2-35*x+2*x-10 = 0

2*x-22*x^2-x^2-31*x-10 = 0

-23*x^2-29*x-10 = 0

-23*x^2-29*x-10 = 0

-1*(23*x^2+29*x+10) = 0

23*x^2+29*x+10 = 0

DELTA = 29^2-(4*10*23)

DELTA = -79

DELTA < 0

-1 = 0

-1/(x*(x-2)) = 0

-1/(x*(x-2)) = 0 // * x*(x-2)

-1 = 0

x belongs to the empty set

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