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5/x+45=10x
We move all terms to the left:
5/x+45-(10x)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
-10x+5/x+45=0
We multiply all the terms by the denominator
-10x*x+45*x+5=0
We add all the numbers together, and all the variables
45x-10x*x+5=0
Wy multiply elements
-10x^2+45x+5=0
a = -10; b = 45; c = +5;
Δ = b2-4ac
Δ = 452-4·(-10)·5
Δ = 2225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2225}=\sqrt{25*89}=\sqrt{25}*\sqrt{89}=5\sqrt{89}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-5\sqrt{89}}{2*-10}=\frac{-45-5\sqrt{89}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+5\sqrt{89}}{2*-10}=\frac{-45+5\sqrt{89}}{-20} $
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