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5/x+2/3x=1
We move all terms to the left:
5/x+2/3x-(1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
15x/3x^2+2x/3x^2-1=0
We multiply all the terms by the denominator
15x+2x-1*3x^2=0
We add all the numbers together, and all the variables
17x-1*3x^2=0
Wy multiply elements
-3x^2+17x=0
a = -3; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-3)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-3}=\frac{-34}{-6} =5+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-3}=\frac{0}{-6} =0 $
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