5/c+3=8/2c

Solution for 5/c+3=8/2c equation:

5/c+3=8/2c

We move all terms to the left:

5/c+3-(8/2c)=0


Domain of the equation: c!=0

c∈R



Domain of the equation: 2c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

5/c-(+8/2c)+3=0

We get rid of parentheses

5/c-8/2c+3=0

We calculate fractions


10c/2c^2+(-8c)/2c^2+3=0

We multiply all the terms by the denominator


10c+(-8c)+3*2c^2=0

Wy multiply elements

6c^2+10c+(-8c)=0

We get rid of parentheses

6c^2+10c-8c=0

We add all the numbers together, and all the variables

6c^2+2c=0

a = 6; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·6·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*6}=\frac{-4}{12}
=-1/3
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*6}=\frac{0}{12}
=0
$