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5/9x=x
We move all terms to the left:
5/9x-(x)=0
Domain of the equation: 9x!=0We add all the numbers together, and all the variables
x!=0/9
x!=0
x∈R
-1x+5/9x=0
We multiply all the terms by the denominator
-1x*9x+5=0
Wy multiply elements
-9x^2+5=0
a = -9; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-9)·5
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{5}}{2*-9}=\frac{0-6\sqrt{5}}{-18} =-\frac{6\sqrt{5}}{-18} =-\frac{\sqrt{5}}{-3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{5}}{2*-9}=\frac{0+6\sqrt{5}}{-18} =\frac{6\sqrt{5}}{-18} =\frac{\sqrt{5}}{-3} $
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