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5/9x-x=-32
We move all terms to the left:
5/9x-x-(-32)=0
Domain of the equation: 9x!=0We add all the numbers together, and all the variables
x!=0/9
x!=0
x∈R
-1x+5/9x+32=0
We multiply all the terms by the denominator
-1x*9x+32*9x+5=0
Wy multiply elements
-9x^2+288x+5=0
a = -9; b = 288; c = +5;
Δ = b2-4ac
Δ = 2882-4·(-9)·5
Δ = 83124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{83124}=\sqrt{36*2309}=\sqrt{36}*\sqrt{2309}=6\sqrt{2309}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(288)-6\sqrt{2309}}{2*-9}=\frac{-288-6\sqrt{2309}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(288)+6\sqrt{2309}}{2*-9}=\frac{-288+6\sqrt{2309}}{-18} $
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