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5/9x-5/6x=-1/3
We move all terms to the left:
5/9x-5/6x-(-1/3)=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: 6x!=0We get rid of parentheses
x!=0/6
x!=0
x∈R
5/9x-5/6x+1/3=0
We calculate fractions
324x^2/486x^2+270x/486x^2+(-405x)/486x^2=0
We multiply all the terms by the denominator
324x^2+270x+(-405x)=0
We get rid of parentheses
324x^2+270x-405x=0
We add all the numbers together, and all the variables
324x^2-135x=0
a = 324; b = -135; c = 0;
Δ = b2-4ac
Δ = -1352-4·324·0
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{18225}=135$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-135)-135}{2*324}=\frac{0}{648} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-135)+135}{2*324}=\frac{270}{648} =5/12 $
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