5/9(g+18)=1/6g=3

Solution for 5/9(g+18)=1/6g=3 equation:

5/9(g+18)=1/6g=3

We move all terms to the left:

5/9(g+18)-(1/6g)=0


Domain of the equation: 9(g+18)!=0

g∈R



Domain of the equation: 6g)!=0

g!=0/1

g!=0

g∈R


We add all the numbers together, and all the variables

5/9(g+18)-(+1/6g)=0

We get rid of parentheses

5/9(g+18)-1/6g=0

We calculate fractions


30g/(54g^2+972g)+(-9gg/(54g^2+972g)=0


We calculate terms in parentheses: +(-9gg/(54g^2+972g), so:

-9gg/(54g^2+972g

We multiply all the terms by the denominator


-9gg

Back to the equation:

+(-9gg)


We get rid of parentheses

30g/(54g^2+972g)-9gg=0

We multiply all the terms by the denominator


30g-9gg*(54g^2+972g)=0

We multiply parentheses

-486g^3-8748g^2+30g=0

We do not support egpression: g^3