5/9(f-32=25

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Solution for 5/9(f-32=25 equation: 



5/9(f-32=25

We move all terms to the left:

5/9(f-32-(25)=0



Domain of the equation: 9(f-32-25!=0

f∈R



We multiply all the terms by the denominator


5!=0

There is no solution for this equation

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