5/9(7-6x)=2(4x-5)

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Solution for 5/9(7-6x)=2(4x-5) equation: 



5/9(7-6x)=2(4x-5)

We move all terms to the left:

5/9(7-6x)-(2(4x-5))=0



Domain of the equation: 9(7-6x)!=0

x∈R



We add all the numbers together, and all the variables

5/9(-6x+7)-(2(4x-5))=0

We multiply all the terms by the denominator


-((2(4x-5)))*9(-6x+7)+5=0



We calculate terms in parentheses: -((2(4x-5)))*9(-6x+7), so:

(2(4x-5)))*9(-6x+7

We add all the numbers together, and all the variables

-6x+(2(4x-5)))*9(+7

Back to the equation:

-(-6x+(2(4x-5)))*9(+7)



We add all the numbers together, and all the variables

-(-6x+(2(4x-5)))*97+5=0

We move all terms containing x to the left, all other terms to the right

-(-6x+(2(4x-5)))*97=-5

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