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5/8x+30=10+1/3x
We move all terms to the left:
5/8x+30-(10+1/3x)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5/8x-(1/3x+10)+30=0
We get rid of parentheses
5/8x-1/3x-10+30=0
We calculate fractions
15x/24x^2+(-8x)/24x^2-10+30=0
We add all the numbers together, and all the variables
15x/24x^2+(-8x)/24x^2+20=0
We multiply all the terms by the denominator
15x+(-8x)+20*24x^2=0
Wy multiply elements
480x^2+15x+(-8x)=0
We get rid of parentheses
480x^2+15x-8x=0
We add all the numbers together, and all the variables
480x^2+7x=0
a = 480; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·480·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*480}=\frac{-14}{960} =-7/480 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*480}=\frac{0}{960} =0 $
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