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5/8x+2/5x=12480
We move all terms to the left:
5/8x+2/5x-(12480)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
25x/40x^2+16x/40x^2-12480=0
We multiply all the terms by the denominator
25x+16x-12480*40x^2=0
We add all the numbers together, and all the variables
41x-12480*40x^2=0
Wy multiply elements
-499200x^2+41x=0
a = -499200; b = 41; c = 0;
Δ = b2-4ac
Δ = 412-4·(-499200)·0
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-41}{2*-499200}=\frac{-82}{-998400} =41/499200 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+41}{2*-499200}=\frac{0}{-998400} =0 $
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