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5/8m-1/2m+1=5
We move all terms to the left:
5/8m-1/2m+1-(5)=0
Domain of the equation: 8m!=0
m!=0/8
m!=0
m∈R
Domain of the equation: 2m!=0We add all the numbers together, and all the variables
m!=0/2
m!=0
m∈R
5/8m-1/2m-4=0
We calculate fractions
10m/16m^2+(-8m)/16m^2-4=0
We multiply all the terms by the denominator
10m+(-8m)-4*16m^2=0
Wy multiply elements
-64m^2+10m+(-8m)=0
We get rid of parentheses
-64m^2+10m-8m=0
We add all the numbers together, and all the variables
-64m^2+2m=0
a = -64; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-64)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-64}=\frac{-4}{-128} =1/32 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-64}=\frac{0}{-128} =0 $
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